169=9p^2

Solution for 169=9p^2 equation:

169=9p^2

We move all terms to the left:

169-(9p^2)=0

a = -9; b = 0; c = +169;
Δ = b2-4ac
Δ = 02-4·(-9)·169
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-78}{2*-9}=\frac{-78}{-18}
=4+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+78}{2*-9}=\frac{78}{-18}
=-4+1/3
$